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Sallen and Key filter

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Sallen and Key filter

What are Sallen-Key filters?

The Sallen–Key topology is used to implement second-order active filters that easily enhance the Q of the filter using controlled positive feedback. The topology is more simple in comparison to other active filter topologies. In 1955, R. P. Sallen and E. L. Key described these filter circuits, and hence they are generally known as Sallen-Key filters.

Sallen-Key low pass filter circuit

Figure 1 shows a RC-RC network that forms a second-order low-pass filter. With R1=R2=R and C1=C2=C, Q=1/3. Q approaches the maximum value of 1/2 if the impedance of the second RC stage is made much larger than the first. Most filters require Qs larger than 1/2.

second order passive low pass filter
Fig 1 : Passive second order low pass filter

The transfer function of a passive second-order low-pass filter is :

$$\cfrac{V_{out}}{V_{in}}=\cfrac{1}{s^2R^2C^2+3sRC+1}$$

$$Q=\cfrac{1}{3}$$

$$\omega{}_o=\cfrac{1}{RC}$$

Larger Qs are attainable by using a positive feedback. If the positive feedback is controlled, and localized to the cut-off frequency of the filter, almost any Q can be realized. Obtaining higher Q is limited mainly by the component tolerances and opamps gain-bandwidth productThe filter cutoff frequency should be much less than opamps’s gain-bandwidth product. Figure 2 shows an opamp in non-inverting gain used in this manner. Capacitor C1, which is not connected to the ground, provides a positive feedback path.

sallen key low pass filter
Fig 2 : A Sallen-Key second order active low pass filter
sallen key lpf equation
sallen key cutoff equation
Q factor sallen key equation
gain sallen key equation
If R1=R2=R and C1=C2=C, the Q factor is :
Q factor simplified equation

From the above equation, it can be concluded that Q > 1/2 can be achieved if Gain (G) > 1. This achievable Q is higher than any passive filter.

Also, keeping G greater than or equal to 3 will make the system unstable. This is because it will cause at least one pole to appear on the right-hand side. This results in either perpetual oscillation or exponential growth in the output amplitude.

active_filter_sallen_key_lpf_explaination_near_fo-1
Fig 3 : How Sallen-Key gets high Q

Intuitively, we can understand the operation in the following steps:

  1. At low frequencies, where C1 and C2 appear as open circuits, the system behaves as an opamp in a non-inverting configuration providing a gain of G (=1+Rf/Rg).
  2. At high frequencies, where C1 and C2 appear as short circuits, the signal is attenuated at the amplifier’s input, the amplifier amplifies this input to its output, and the signal does not appear at Vo.
  3. Near the cut-off frequency, if gain G is set close to but less than 3 (e.g., 2.5), Vo becomes very high which is basically feeding current through C1 from Vo to vx. This increases the input at the non-inverting pin (vy) resulting in high Q of this filter.

Sallen-Key high pass filter circuit

Figure 3 shows a two-stage RC network that forms a second-order high-pass filter. For simplicity, if R1=R2=R and C1=C2=C, Q=1/3. This low Q results in attenuation in the desired passband and not enough attenuation in the stop band. A higher Q is desired. A higher Q is achievable using an opamp and some positive feedback. This is similar to how we made the Sallen-Key low-pass filter.

second_order_passive_hpf-1
Fig 4 : A second order passive low pass filter

The transfer function of a passive second-order high-pass filter is :

hpf second order equation
Q of 2nd order sallen key filter
omega o 2nd order low pass filter
sallen_key_hpf-1
Fig 5 : Sallen-Key second order active high pass filter

Figure 5 mentions a Sallen-Key high pass filter. Instead of R1 connected to the ground, it is connected to the output of the amplifier to provide positive feedback. Intuitively, we can understand the operation in the following steps:

  1. At low frequencies, where C1 and C2 appear as open circuits, R2 is pulling down the non-inverting node to the ground. This means no signal is getting amplified.
  2. At high frequencies, where C1 and C2 appear as short circuits, vi completely appears at the non-inverting pin of the opamp because the impedance of C2 is lower than R2.
  3. Near the cut-off frequency, similar to the Sallen-Key low pass filter, a current is injected through R1 into C2 from the Vo node. This leads to higher signal strength at the non-inverting pin which results in higher Q.
sallen key hpf equation
sallen key cutoff equation
Q factor sallen key hpf equation

Quick Calculators

RC circuit
Time Constant (s) =

Cutoff Frequency (Hz) =

Time Constant (s) =

Cutoff Frequency (Hz) =

Impedance magnitude (Ω) =

Resonant frequency (Hz) =

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